A fair coin is tossed four times. What is the probability that the sequence of tosses is HHHT? ?
- PinkgreenLv 7Il y a 1 mois
- Il y a 1 mois
None of the answers so far, allow for unconventional results. Such as settling on edge or not landing at all. Oh - and they ignore schrodinger principle, where the coin is captured in flight and exists in an indeterminate state. But......this is why I got into trouble in high school math, for being a smartass. I wasn't - these are conditions a good software designer accounts for. Hey - I never even mentioned Heiseberg !!!
- busterwasmycatLv 7Il y a 1 mois
1 in 16. there are 16 possible orders that can arise. that is one of the 16. 2x2x2x2.
- Iggy RockoLv 7Il y a 1 mois
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- MorningfoxLv 7Il y a 1 mois
There are 16 possible sequences, each with the same probability. So the probability of any particular sequence is 1 / 16.
- ?Lv 7Il y a 1 mois
There are 2 possibilities that can occur at each toss.
so, 2 x 2 x 2 x 2 = 16 ways in total
H, H, H and T is a specific order and one unique combination
- !!!Lv 7Il y a 1 mois